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0x1.0p-23f -> ldexp(1.0, -23) In the second example, the 6 is the number of hexadecimal digits that were after the dot. The original had 0x1.fffffe so when I wrote the integer 0x1fffffe, I wrote a quantity 2 4 times larger for each digit I shifted from after the point to before the point, which should be compensated for with the second argument.
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