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Answer: The value of icap. (icapXjcap) is 0 Explanation: It is assumed that the equation is icap. (icap X jcap) Using the thumb rule icap X jcap would direct in the direction of kcap Therefore icap X jcap = kcap Now, icap.kcap icap.kcap = 0 as the dot product between similar vectors is 1 whereas the dot product between different vectors is 0.
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